1x^2+13x-8=0

Solution for 1x^2+13x-8=0 equation:

1x^2+13x-8=0

We add all the numbers together, and all the variables

x^2+13x-8=0

a = 1; b = 13; c = -8;
Δ = b2-4ac
Δ = 132-4·1·(-8)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{201}}{2*1}=\frac{-13-\sqrt{201}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{201}}{2*1}=\frac{-13+\sqrt{201}}{2}
$